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X^2+3X-928=0
a = 1; b = 3; c = -928;
Δ = b2-4ac
Δ = 32-4·1·(-928)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3721}=61$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-61}{2*1}=\frac{-64}{2} =-32 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+61}{2*1}=\frac{58}{2} =29 $
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